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Prove that: 2sin68°/cos22° – 2cot15°/5tan75° – 3tan45°tan20°tan40°tan50°tan70°/5 = 1

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This question is from trigonometry topic – trigonometric ratios on complementary angles

We have been asked to prove that 2sin68°/cos22° – 2cot15°/5tan75° – 3tan45°tan20°tan40°tan50°tan70°/5 = 1

RS Aggarwal, Class 10, chapter 12, question no 4(iii)

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