In this question we have to the find the area of
the shaded region.OABC is a square of side 7 cm.
If OAPC is a quadrant of a circle with centre O.
This question is from r d sharma class 10 maths.
I found this question while doing mensuration of
class 10.
I need help in getting the solution.
Given,
OABC is a square of side 7 cm
So, OA = AB = BC = OC = 7 cm
Area of square OABC = side2 = 72 = 49 cm2
And given, OAPC is a quadrant of a circle with centre O.
So, the radius of the quadrant = OA = OC = 7 cm
Area of the quadrant OAPC = 90/360 x πr2
= ¼ x (22/7) x 72
= 77/2 = 38.5 cm2
Thus,
Area of shaded portion = Area of square OABC – Area of quadrant OAPC
= (49 – 38.5) = 10.5 cm2