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Rajan@2021
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In the given fig. DE ∥ BC. If AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, find the value of x.

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In the given figure we have given length of sides of the triangle in terms of X and we need to find the value of X by using the properties of similarities

ML Aggarwal Avichal Publication Class 10, Similarity, Chapter 13ii,  question no 2i

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1 Answer

  1. In Δ ABC, DE  BC
    AD/DB=AE/EC
    (By basic proportionality theorem)
    ⇒x/x2x=x+2/x-1
    x(x1)=(x+2)(x2)
    x^2x=x^24

    x=4.

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