In the given figure we have been asked to find
(i) area of triangle CDP,
(ii) area of parallelogram ABCD.
Given that P is a point on BC of parallelogram ABCD such that BP : PC = 1 : 2. DP produced meets AB produces at Q. Given the area of triangle CPQ = 20 cm2.
Book- ML Aggarwal Avichal Publication class 10, similarity, chapter 13.3, question no 12