0 Rajan@2021Guru Asked: April 9, 20212021-04-09T08:42:48+05:30 2021-04-09T08:42:48+05:30In: CBSE If sec4A = cosec(A-15°), where 4A is an acute angle, find the value of A 0 This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have to find the value of A, if sec4A = cosec(A-15°) RS Aggarwal, Class 10, chapter 12, question no 14 class 10rs aggarwaltrigonometric ratios Share Facebook 1 Answer Voted Oldest Recent MathsMentor Guru 2021-04-11T10:41:42+05:30Added an answer on April 11, 2021 at 10:41 am sec4A=cosec(A−15o) (given) ⇒cosec(90°−4A)=cosec(A−15°) ⇒90°−4A=A−15° ⇒A+4A=90°+15° ⇒5A=105° ⇒A=21° The value of A=21° 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Speed of a boat in still water is 15 km/h. It goes 30 km upstream and returns back ... Find the values of k for which the pair of linear equations kx + 3y = k-2 and ... . Solve for x and y: 0.4x-1.5y = 6.5, 0.3x-0.2y=0.9. Solve graphically the system of linear equations 4x-5y +16=0 and 2x+y-6 = 0. Determine the vertices of the ... If the remainder on division of x3 + 2x2 + kx +3 by x – 3 is 21, ...

sec4A=cosec(A−15o) (given)

⇒cosec(90°−4A)=cosec(A−15°)

⇒90°−4A=A−15°

⇒A+4A=90°+15°

⇒5A=105°

⇒A=21°

The value of A=21°