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If 12 cosec θ = 13, find the value of (2 sin θ – 3 cos θ)/ (4 sin θ – 9 cos θ)

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This ques has been taken from the Book- ML Aggarwal
Board- ICSE
Publication- Avichal

Chapter 18th
Chapter- Trigonometric Identities

This has been asked in previous year question

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If 12 cosec θ = 13, find the value of (2 sin θ – 3 cos θ)/ (4 sin θ – 9 cos θ)

ML Aggarwal, ICSE, class10, chapter 18, question no 5

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1 Answer

  1. Given,

    12 cosec θ = 13

    ⇒ cosec θ = 13/12

    In right ∆ ABC,

    ∠A = θ

    So, cosec θ = AC/BC = 13/12

    AC = 13 and BC = 12

    By Pythagoras theorem,

    AB = √(AC2 – BC2)

    = √[(13)2 – (12)2]

    = √(169 – 144)

    = √25

    = 5

    Now,

    sin θ = BC/AC = 12/13

    cos θ = AB/AC = 5/13

    Hence,

    ML Aggarwal Solutions for Class 10 Chapter 18 - 4

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