One of the important question from factorisation chapter in which we have been asked to find the value of k for which x=3 is a solution of the quadratic equation, (k+2)x2−kx+6=0.
Thus find the other root of the equation.
ML Aggarwal(Avichal Publication), Factorisation chapter 6, Question no 21
Given : (k+2)x2−kx+6=0
Putting x=3
(k+2)×9−k×3+6=0
9k+18−3k+6=0
6k=−24
k=−4
Putting k=−4 in given equation
−2x2+4x+6=0
x2−2x−3=0
x2−3x+x−3=0
x(x−3)+1(x−3)=0
(x+1)(x−3)=0
x+1=0 or x−3=0
x=−1 or x=3
Other root of the equation, x=−1