The question is given from ncert Book of class 10th Chapter no. 5 Ex. 5.3 Q. 1 (ii). In the following question you have to find The sum of the A.P given above in the question give the answer of the question briefly.

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Given, −37, −33, −29 ,…, to 12 terms

For this A.P.,

first term, a = −37

And common difference, d = a

_{2}− a_{1}d= (−33)−(−37)

= − 33 + 37 = 4

n = 12

We know that, the formula for sum of nth term in AP series is,

S

_{n}= n/2 [2a+(n-1)d]S

_{12}= 12/2 [2(-37)+(12-1)×4]= 6[-74+11×4]

= 6[-74+44]

= 6(-30) = -180