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Rajan@2021
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Find the sum of first 100 even natural numbers which are divisible by 5.

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We have a question from arithmetic progression chapter in we have given first 100 even natural numbers which are divisible by 5 and we have to find their sum.

Book – RS Aggarwal, Class 10, chapter 5C, question no 18

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  1. Even natural numbers: 2,4,6,8,10,....
    Even natural numbers divisible by 510,20,30,40,.... to 100 terms
    Here, a=10,d=2010=10, and n=100
    We have,
    Sn=n/2(2a+(n1)d)
    =100/2[2×10+(1001)10]
    =50500.

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