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Rajan@2021
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Divide 24 in three parts such that they are in AP and their product is 440.

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One of the basic question from arithmetic progression chapter in which we are to find 3 numbers such that they are in AP if their product is 440 and their sum is 24.

RS Aggarwal, Class 10, chapter 5B, question no 8.

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1 Answer

  1. Let ad,a,a+d are three numbers in AP.
    their sum =ad+a+a+d=24
    3a=24
    or a=8
    Again,
    Their product =(ad)×a×(a+d)=440
    a(a^2d^2)=440
    8(8^2d^2)=440
    or d=±3

    We have 2 conditions here:
    At a=8,d=3
    Numbers are: 5,8 and 11
    At a=8 and d=3
    Numbers are: 11,8,5.

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