This question is from r d sharma class 10 maths.
I found this question while doing maths class 10.
I need help in getting the solution.
In this question we have to find the height of the embankment
from a well with inner radius 4 m is
dug up and 14 m deep. Earth taken out of it has spread evenly
all around a width of 3 m it to form an embankment.
Given,
Inner radius of the well = 4 m
Depth of the well = 14 m
We know that,
Volume of the cylinder = π r2h
= π × 42 × 14 …. (i)
From the question, it’s told that
The earth taken out from the well is evenly spread all around it to form an embankment
And, the width of the embankment = 3 m
So, the outer radius of the well = 3 + 4 m = 7 m
We know that,
Volume of the hollow embankment = π (R2 – r2) × h
= π × (72 – 42) × h …… (ii)
On equating both the equations (i) and (ii), we get
π × 42 × 14 = π × (72 – 42) × h
h = 42 × 14 / (33)
h = 6.78 m
Therefore, the height of the embankment so formed is 6.78 m.