If you open math book you will find a lot of mathematical questions but

youshould have solve this question.

It is from class 10 rd sharma chapter 16 mensuration .

In this question we have to find the the cost of the canvas at Rs. 3.50 per m2

given that a tent of height 77 dm is in the form of a right circular cylinder

of diameter 36 m and height 44 dm surmounted by a right circular cone.

Given,

Height of the tent = 77 dm

Height of a surmounted cone = 44 dm

Height of the Cylindrical Portion = Height of the tent â€“ Height of the surmounted Cone

= 77 â€“ 44

= 33 dm = 3.3 m

And, given diameter of the cylinder (d) = 36 m

So, its radius (r) of the cylinder = 36/2 = 18 m

Letâ€™s consider L as the slant height of the cone.

Then, we know that

L2 = r2 + h2

L2 = 182 + 3.32

L2 = 324 + 10.89

L2 = 334.89

L = 18.3 m

Thus, slant height of the cone (L) = 18.3 m

Now, the Curved Surface area of the Cylinder (S1) = 2Ï€rh

S1 = 2Ï€ (184.4) m2

And, the Curved Surface area of the cone (S2) = Ï€rL

S2 = Ï€ Ã— 18 Ã— 18.3 m2

So, the total curved surface of the tent (S) = S1 + S2

S = S1 + S2

S = (2Ï€18 Ã— 4.4) + (Ï€18 Ã— 18.3)

S = 1533.08 m2

Hence, the total Curved Surface Area (S) = 1533.08 m2

Next,

The cost of 1 m2 canvas = Rs 3.50

So, 1533.08 m2 of canvas will cost = Rs (3.50 x 1533.08)

= Rs 5365.8