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A tent consists of a frustum of a cone capped by a cone. If radii of the ends of the frustum be 13 m and 7 m, the height of frustum be 8 m and the slant height of the conical cap be 12 m, find the canvas required for the tent.

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If you open math book you will find a lot of mathematical
questions butyou should have solve this question.
It is from class 10 rd sharma chapter 16 mensuration .

In this question we have to find the canvas required for
the tent given that a tent consists of a frustum of a
cone capped by a cone. If radii of the ends of the frustum
be 13 m and 7 m, the height of frustum be 8 m and the slant
height of the conical cap be 12 m.

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1 Answer

  1. Given,

    Height of frustum (h) = 8 m

    Radii of the frustum cone are 13 cm and 7 cm

    So, r1 = 13 cm and r2 = 7 cm

    Let ‘L’ be slant height of the frustum cone

    Then, we know that

    Curved surface area of the frustum (s1) = π(r1 + r2) × L = π(13 + 7) × 10 = 200 π m2

    Then, given slant height of conical cap = 12 m

    Base radius of upper cap cone = 7 m

    So, the curved surface area of upper cap cone (s2) = πrl = π × 7 × 12 = 264 m2

    Thus, the total canvas required for tent (S) = s1 + s2

    S = 200π + 264 = 892.57 m2

    Therefore, the canvas required for the tent is 892.57 m2.

     

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