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A bucket is in the form of a frustum of a cone of height 30 cm with radii of its lower and upper ends as 10 cm and 20 cm respectively. Find the capacity and surface area of the bucket. Also, find the cost of milk which can completely fill the container, at the rate of Rs.25 per litre.

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Very important question of mensuration including
very important concept of it.need solution!
Rd sharma class 10 maths exercise-16.3 mensuration.

we have to find the capacity and the surface area of
the bucket and the cost of milk which can completely
fill the container, at the rate of Rs.25 per litre
given that a bucket is in the form of a frustum of a
cone of height 30 cm with radii of its lower and upper
ends as 10 cm and 20 cm respectively.

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1 Answer

  1. Let R and r be the radii of the top and base of the bucket respectively,

    Let h be its height.

    Then, we have R = 20 cm, r = 10 cm, h = 30 cm

    Capacity of the bucket = Volume of the frustum of the cone

    = 1/3 π(R2 + r2 + R r )h

    = 1/3 π(202 + 102 + 20 x 10 ) x 30

    = 3.14 x 10 (400 + 100 + 200)

    = 21980 cm3 = 21.98 litres

    Now,

    Surface area of the bucket = CSA of the bucket + Surface area of the bottom

    = π l (R + r) + πr2

    We know that,

    l = √h2 + (R – r)2

    = √[302 + (20 – 10)2] = √(900 + 100)

    = √1000 = 31.62 cm

    So,

    The Surface area of the bucket = (3.14) x 31.62 x (20 + 10) + (3.14) x 102

    = 2978.60 + 314

    = 3292.60 cm2

    Next, given that the cost of 1 litre milk = Rs 25

    Thus, the cost of 21.98 litres of milk = Rs (25 x 21.98) = Rs 549.50

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