0 SanuByahutNewbie Asked: November 28, 20222022-11-28T23:03:40+05:30 2022-11-28T23:03:40+05:30In: CBSE 2.2 cubic dm of brass is to be drawn into a cylindrical wire of 0.25 cm in diameter. Find the length of the wire? 0 This question is of chapter 16, exercise 16.1 mensuration from rd sharma. In this question we have to find length of the wire. Please someone provide me solution. cbse class 10maths class 10mensuration solutionrd sharma solution Share Facebook 1 Answer Voted Oldest Recent PayalArora Newbie 2022-12-01T10:01:03+05:30Added an answer on December 1, 2022 at 10:01 am 2.2 dm^{3}Â of brass is to be drawn into a cylindrical wire of Diameter = 0.25 cm So, radius of the wire (r) = d/2 = 0.25/2 = 0.125*10^{-2Â }cm Now, 1 cm = 0.01 m So, 0.1cm = 0.001 m Let the length of the wire be (h) We know that, Volume of the cylinder = Ï€r^{2}h Itâ€™s understood that, Volume of cylindrical wire = Volume of brass of 2.2 dm^{3} h = 448 m Therefore, the length of the cylindrical wire drawn is 448 m 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions A plot in the form of a rectangle ABCD having semi-circle on BC as shown in Fig.15.64. If ... The slant height of the frustum of a cone is 4 cm and the perimeters of its circular ... A bucket has top and bottom diameters of 40 cm and 20 cm respectively. Find the volume of ... A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of ... A vessel in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the ...

2.2 dm

^{3}Â of brass is to be drawn into a cylindrical wire of Diameter = 0.25 cmSo, radius of the wire (r) = d/2

= 0.25/2 = 0.125*10

^{-2Â }cmNow, 1 cm = 0.01 m

So, 0.1cm = 0.001 m

Let the length of the wire be (h)

We know that,

Volume of the cylinder = Ï€r

^{2}hItâ€™s understood that,

Volume of cylindrical wire = Volume of brass of 2.2 dm

^{3}h = 448 m

Therefore, the length of the cylindrical wire drawn is 448 m