This is the basic and conceptual question from linear equations in two variables as it was already asked in various examinations in which we have to find the number if the sum of two numbers is 16 and the sum of their reciprocals is 1/3.
Kindly solve the above problem
Book- RS Aggarwal, Class 10, chapter 3E, question no 24
Let the the parts be x and y
x+y=16
⇒1/x+1/y=1/3
⇒16/xy=1/3
⇒y²−16y+48=0
⇒(y−12)(y−4)=0
⇒y=4 x=12,
or y=12, x=4